X^2+14x=527

Solution for X^2+14x=527 equation:

X^2+14X=527

We move all terms to the left:

X^2+14X-(527)=0

a = 1; b = 14; c = -527;
Δ = b2-4ac
Δ = 142-4·1·(-527)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-48}{2*1}=\frac{-62}{2}
=-31
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+48}{2*1}=\frac{34}{2}
=17
$